SOLUTION: Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liters of each solution should be mixed to make 4.5 liters of a 40%-alcohol solut

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liters of each solution should be mixed to make 4.5 liters of a 40%-alcohol solut      Log On

Hi

Let x and (4.5-x)represent the amount of the 50% and 20% solution respectively

Question states***

  .50x + .20(4.5 -x) = .40*4.5L

Solving for x

     .30x = .20*4.5L

Will let You finish it up