You can put this solution on YOUR website! given:
f(x) = 2x^2 + 8x + c
we know that it is a parabola that opens upwards (because of the positive coefficient associated with the x^2 term).
Therefore, the vertex gives you the minimum.
.
x-coordinate of minimum:
x = -b/(2a) = -8/(2*2) = -8/4 = -2
.
f(x) = 2x^2 + 8x + c
-11 = 2(-2)^2 + 8(-2) + c
-11 = 2(4) + (-16) + c
-11 = 8 - 16 + c
-11 = -8 + c
-3 = c
