SOLUTION: i have a picture of a triangle and the lenght is (3n+1) and the width is (2n-5)
and it says "write the area as a trinomial."
i got
6n^2+13n-5
but it said i was wrong so how
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: i have a picture of a triangle and the lenght is (3n+1) and the width is (2n-5)
and it says "write the area as a trinomial."
i got
6n^2+13n-5
but it said i was wrong so how
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Question 40860: i have a picture of a triangle and the lenght is (3n+1) and the width is (2n-5)
and it says "write the area as a trinomial."
i got
6n^2+13n-5
but it said i was wrong so how do i do these problems? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! AREA OF A TRIANGLE IS 1/2BASE*HEIGHT. SO WE HAVE 1/2(3N+1)(2N-5) OR
1/2(6N~2-13N-5) OR (6N~2-13N-5)/2
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