SOLUTION: A refrigerated case holds 24 cans of soft drinks: 6 cola, 6 root beer, 3 orange, 3 sparkling water, and 6 ginger ale. If one can is drawn at random, what is the probability of gett

Algebra ->  Probability-and-statistics -> SOLUTION: A refrigerated case holds 24 cans of soft drinks: 6 cola, 6 root beer, 3 orange, 3 sparkling water, and 6 ginger ale. If one can is drawn at random, what is the probability of gett      Log On


   

Question 408470: A refrigerated case holds 24 cans of soft drinks: 6 cola, 6 root beer, 3 orange, 3 sparkling water, and 6 ginger ale. If one can is drawn at random, what is the probability of getting
(a) a can of root beer
(b) a can of cola or a can of ginger ale
(c) a can that is neither cola, root beer, nor ginger ale

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

24 cans of soft drinks: one can is drawn at random from:

 6 cola, 6 root beer, 3 orange, 3 sparkling water, and 6 ginger ale.

P(a can of root beer) = 6/24 = 1/4

P((b) a can of cola 'or' a can of ginger ale) = 1/4 + 6/24 = 1/2

P(a can that is neither cola, root beer, nor ginger ale)= 1-18/24 = 6/24 = 1/4