SOLUTION: solve using a system of equations.
I know you have to do something like x+y+x+y=, but then I get so confused.
A 40% saline solution is to be mixed with a 60% saline solution
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I know you have to do something like x+y+x+y=, but then I get so confused.
A 40% saline solution is to be mixed with a 60% saline solution
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Question 408464: solve using a system of equations.
I know you have to do something like x+y+x+y=, but then I get so confused.
A 40% saline solution is to be mixed with a 60% saline solution to obtain 8 liters of a 55% solution. How many liters of each solution should be used? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! In words:
(liters of salt in 40% solution + liters of salt in 60% solution)/(liters of solution) = 55%
Let = liters of 40% solution needed
Let = liters of 60% solution needed
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given: = salt in 40% solution = salt in 60% solution
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(1)
(2)
This is 2 equations and 2 unknowns, so it's solvable
----------------------
(1)
(1)
(1)
(1)
and, also,
(2)
(2)
Subtract (2) from (1)
(1)
(2)
and, since
(2)
2 liters of 40% solution and 6 liters of 60% solution are needed
check answer:
(1)
(1)
OK
