SOLUTION: A cylindrical tin has an internal diameter of 18 cm. It contains water to a height of 13.2 cm. How far will the water level rise when a heavy ball 9.3 cm in diameter is immersed in

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Question 40807: A cylindrical tin has an internal diameter of 18 cm. It contains water to a height of 13.2 cm. How far will the water level rise when a heavy ball 9.3 cm in diameter is immersed in it ?
Answer by astromathman(21) About Me  (Show Source):
You can put this solution on YOUR website!
First, note that it is clear that the ball will be completely submerged. If this were not so, we would have to be more careful. Since it IS so, the ball simply pushes up an equal volume of water, so we can add the volume of the ball to the volume of the water as though it were all water.
Vol%5BC%5D=A%5Bb%5Dh+=%28pi+%2Ar%5E2%29%2Ah and Vol%5BS%5D=%284%2F3%29%2A+pi+%2Ar%5E3
Using these, the ball has volume 421%28cm%5E3%29 and the volume of the water in the can is 3359%28cm%5E3%29 for a total of 3780%28cm%5E3%29. Setting %28pi+%2A9%5E2%29%2Ah=3780 and solving for h yields h=3780%2F%2881pi%29+=+14.85%2Acm.
(Answers will vary slightly depending on whether you use your calculator's version of pi or type in 3.14.)