SOLUTION: Hi Finding this difficult, new to this can someone please help If z=2+j is one root of the equation z^4-2z^3-z^2+2z+10=0 find the other roots Many Thanks Karl

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Hi Finding this difficult, new to this can someone please help If z=2+j is one root of the equation z^4-2z^3-z^2+2z+10=0 find the other roots Many Thanks Karl      Log On


   



Question 407894: Hi
Finding this difficult, new to this can someone please help
If z=2+j is one root of the equation z^4-2z^3-z^2+2z+10=0 find the other roots
Many Thanks
Karl

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!


z=2+j is one root of the equation z4 - 2z³- z²+ 2z + 10 = 0

We use synthetic division:

   2+j|1    -2      -1         2         10
      |      2+j    -1+2j     -6+2j     -10                
       1       j    -2+2j     -4+2j       0

So we have factored the polynomial as

 [z - (2+j)][z³+ jz²+ (-2+2j)z + (-4+2j)z] = 0

Next we factor the cubic polynomial, since we know that if
2+j is a root, its conjugate 2-j is also a root


   2-j|1       j    -2+2j     -4+2j
      |      2-j     4-2j      4-2j
       1     2       2         0

So we have now factored the polynomial as

 [z - (2+j)][z - (2-j)](z²+ 2z + 2) = 0

We set each equal to 0

Setting the first two factors = 0 just gives z = 2+j and z = 2-j.

Setting the third factor = 0 gives

     z²+ 2z + 2 = 0

z+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

z+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A2+%29%29%2F%282%2A1%29+

z+=+%28-2+%2B-+sqrt%284-8%29%29%2F2+

z+=+%28-2+%2B-+sqrt%28-4%29%29%2F2+

z+=+%28-2+%2B-+2j%29%2F2+

z+=+2%28-1+%2B-+j%29%2F2+

z+=+cross%282%29%28-1+%2B-+j%29%2Fcross%282%29+

z = -1±j

So the roots other than the given one, 2+j, are 2-j, -1+j and -1-j

Edwin