SOLUTION: A woman can bicycle 28 miles in the same time as it takes her to walk 8 miles. She can ride 10 mph faster than she can walk. How fast can she walk?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A woman can bicycle 28 miles in the same time as it takes her to walk 8 miles. She can ride 10 mph faster than she can walk. How fast can she walk?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 407757: A woman can bicycle 28 miles in the same time as it takes her to walk 8 miles. She can ride 10 mph faster than she can walk. How fast can she walk?

Found 2 solutions by mananth, Tatiana_Stebko:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
walk rate = x mph
cycling rate = x+10 mph
walking distance = 8 miles
cycling distance = 28 miles
..
t= d/r
..
time riding = time walking
8/x=28/(x+10)
cross multiply
8(x+10)=28x
8x+80=28x
28x-8x=80
20x=80
/20
x= 4 walking rate
cycling rate = 4+10 =14 mph

Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
If woman can walk xmph, then she can ride %28x%2B10%29 mph (because she can ride 10 mph faster than she can walk)
Woman ride 28 miles by 28%2F%28x%2B10%29 hours, and can walk 8 miles by 8%2Fx hours.
Equation
28%2F%28x%2B10%29=8%2Fx
28x=8%28x%2B10%29
28x=8x%2B80
20x=80
x=80%2F20
x=4
Woman can walk 4mph