SOLUTION: write an equation in slope-intercept form of the line satisfying the following conditions:
through (3,6); perpendicular to x=4
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-> SOLUTION: write an equation in slope-intercept form of the line satisfying the following conditions:
through (3,6); perpendicular to x=4
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Question 407657: write an equation in slope-intercept form of the line satisfying the following conditions:
through (3,6); perpendicular to x=4 Answer by graphmatics(170) (Show Source):
You can put this solution on YOUR website! The Line equation is y-y1 = m*(x-x1) where m is the slope of the line.
As line is perpendicular to a line with slope m if its slope is 1/m.
So for a point (x,y) on the line m = (y-y1)/(x-x1).
if x = 4 for a line then m = (y-y1)/(4-4) = infinity.
the perpendicular has a slope of 1/infinity or 0.
so the equation of the line in question is
y-6 = 0*(x-3)
y-6 = 0
y = 6
