SOLUTION: A printing company purchased a new copier that is twice as fast as the old copier. With both copiers working at the same time, it takes 10 hours to do a job. How long would it take

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A printing company purchased a new copier that is twice as fast as the old copier. With both copiers working at the same time, it takes 10 hours to do a job. How long would it take      Log On


   



Question 407642: A printing company purchased a new copier that is twice as fast as the old copier. With both copiers working at the same time, it takes 10 hours to do a job. How long would it take the new copier working alone
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A printing company purchased a new copier that is twice as fast as the old copier.
With both copiers working at the same time, it takes 10 hours to do a job.
How long would it take the new copier working alone
:
Let t = time required by the new copier working alone
then
2t = time required by the old copier alone
:
Let the completed job = 1
:
A typical shared work equation:
:
10%2Ft + 10%2F%282t%29 = 1
Multiply by 2t, results
2(10) + 10 = 2t
30 = 2t
t = 30%2F2
t = 15 hrs the new copier working alone
:
:
:
Check this:
10/15 + 10/30 =
2/3 + 1/3 = 1; confirms our solution of t = 15