SOLUTION: equation in point-slope-intercept form (-3,-2),(5,3)

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Question 407597: equation in point-slope-intercept form
(-3,-2),(5,3)
Answer by MathLover1(20850) About Me  (Show Source):
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, -2) and (x2, y2) = (5, 3).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%283--2%29%2F%285--3%29+=+0.625.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0.625%2A-3+%2Bb+=+-0.125. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-2-0.625%2A-3+=+-0.125.

y=(0.625)x + (-0.125)

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