SOLUTION: Line 2 is perpendicular to a line that passes through the points (4,-3) and (-2,6). How do I find the slope intercept (y=mx+b) and the general form (Ax+By=C)?
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-> SOLUTION: Line 2 is perpendicular to a line that passes through the points (4,-3) and (-2,6). How do I find the slope intercept (y=mx+b) and the general form (Ax+By=C)?
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Question 40703: Line 2 is perpendicular to a line that passes through the points (4,-3) and (-2,6). How do I find the slope intercept (y=mx+b) and the general form (Ax+By=C)? Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! Slope = (y2 - y1)/(x2 - x1) = (6 + 3)/(-2 - 4) = 9/(-6) = 3/(-2)
Perpendicular to this slope, so it is:
You are missing the information that tells us what point or points the new line goes through. Does it go through of the points you gave for the other line?
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