Question 407010: how do i solve (3y-1)^6=80 using logarithms?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! how do i solve (3y-1)^6=80 using logarithms?
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I'm not sure logarithms is the best method to use, but you can easily solve it with regular algebra and a good calculator.
(3y-1)^6=80
raise each side to the (1/6) power
3y-1=80^(1/6)=2.076
3y=2.076+1=3.076
y=3.076/3=1.025
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Anyway, if you want to do it by logs, this is how you do it:
6log(3y-1)=log80
log(3y-1)=log80/6=.31718
change to exponential form,
3y-1=10^.31718=2.0758
3y=2.0758+1=3.0758
y=3.0758/3=1.025
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