Hi
A parabolic arch has a span of 100 feet and a maximum height of 25 feet.
Using the vertex form of a parabola,
where(h,k) is the vertex
y = a(x-50)^2 + 25 Vertex (50,25)
0 = a50^2 + 25 |Using x-intercept Pt(0,0) to solve for a
-25/2500 = a
y = (-1/100)(x-50)^2 + 25
height of the arch 20 feet from the center:
x = 30
y = (-1/100)20^2 + 25
y = -4 + 25
y = 21ft