SOLUTION: the relationship between two currents in a circuit is given by I1+I2=14 and 3I+I2=30.Calculate I1 and I2. how do you go about this one,please assist.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: the relationship between two currents in a circuit is given by I1+I2=14 and 3I+I2=30.Calculate I1 and I2. how do you go about this one,please assist.      Log On


   

Question 406798: the relationship between two currents in a circuit is given by I1+I2=14 and 3I+I2=30.Calculate I1 and I2.
how do you go about this one,please assist.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,You are absolutely correct! 

A great example of why "checking the answer" works!

I%5B1%5D+%2B+I%5B2%5D+=+14

3I%5B1%5D%2B+I%5B2%5D+=+30

Solving by Elimination |Subtracting 1st equation from 2nd

-I%5B1%5D+-+I%5B2%5D+=+-14

3I%5B1%5D%2B+I%5B2%5D+=+30

    2I%5B1%5D+=+16

       I%5B1%5D=8 AND I%5B2%5D+=+6  (14-8)



CHECKING our Answer***

3I%5B1%5D%2B+I%5B2%5D+=+30

3%2A8%2B+6+=+30