Question 406668:  I have two questions, the 1st one is:
 
#1. The product of two numbers is 10 less than 16 times the smaller. if twice the smaller is 5 more than the larger number, find the two numbers.
 
I'm having trouble with the first one. The second problem is this:
 
#2.  The area of a rectangular field is 162 sq. m. and its length is twice its width. Find the dimensions of the field.
 
In number 2 I did this:
 
Let x = width 
    2x = length
 
  (2x)(x) = 162 
>  2x^2 = 162 
>  2x^2/2 = 162/2 
>  x^2 = 81 
>  x = 9
 
I just wanna ask if my answer is correct or do I have to continue and it like this: 
>  2x 
>  2(9) 
>  = 18
 
Looking forward for your response. 
 Answer by nerdybill(7384)      (Show Source): 
You can  put this solution on YOUR website! #1. The product of two numbers is 10 less than 16 times the smaller. if twice the smaller is 5 more than the larger number, find the two numbers.  
. 
Let x = smaller of two numbers 
and y = larger of two numbers 
. 
from: "The product of two numbers is 10 less than 16 times the smaller" we get: 
xy = 16x-10 (equation 1) 
from: "twice the smaller is 5 more than the larger number" we get: 
2x = y+5 (equation 2) 
. 
Solving equation 1 for y: 
xy = 16x-10 
y = (16x-10)/x 
Plug above into equation 2 and solve for x: 
2x = y+5 
2x = (16x-10)/x+5 
multiplying both sides by x: 
2x^2 = (16x-10)+5x 
2x^2 = 21x-10 
2x^2 - 21x + 10 = 0 
(2x-1)(x-10) = 0 
x = {1/2, 10} 
throw out the 1/2 leaving: 
x = 10 
. 
to find y, plug above into: 
xy = 16x-10 
10y = 160-10 
10y = 150 
y = 15 
.  
solution: the two numbers are 10 and 15
 
. 
#2. The area of a rectangular field is 162 sq. m. and its length is twice its width. Find the dimensions of the field.  
In number 2 I did this:  
Let x = width 
2x = length  
(2x)(x) = 162 
> 2x^2 = 162 
> 2x^2/2 = 162/2 
> x^2 = 81 
> x = 9  
I just wanna ask if my answer is correct or do I have to continue and it like this: 
> 2x 
> 2(9) 
> = 18 
 
Yes, you must -- because the problem is asking for "the dimensions". 
x gives you only the width 
you need to find the length also 
complete answer would be 9 meters by 18 meters 
(don't forget your units) 
 
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