SOLUTION: Hello...Can someone please help me with this question:A cable television company needed to wire from its box at the corner of a lot to a corner of a house. The owner knew the house
Algebra ->
Pythagorean-theorem
-> SOLUTION: Hello...Can someone please help me with this question:A cable television company needed to wire from its box at the corner of a lot to a corner of a house. The owner knew the house
Log On
Question 406649: Hello...Can someone please help me with this question:A cable television company needed to wire from its box at the corner of a lot to a corner of a house. The owner knew the house was 15ft. from the side of the lot and 60ft from the back of the lot. How much wire was needed to go from the box to the house?(To be rounded to the nearest tenths)...Thank you in advance! Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Basically they form a right triangle
Hypotenuse is the wire length
leg1=15ft
leg2=60 ft
..
15^2+60^2= wire length^2
225 +3600=wire length^2
3825= wire length ^2
wire length = sqrt(3825)
wire length =61.8 ft
