SOLUTION: A newspaper carrier has $3.75 in change. He has three more quarters than dimes but twice as many nickels as quarters. How many coins of each type does he have?

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Question 406117: A newspaper carrier has $3.75 in change. He has three more quarters than dimes but twice as many nickels as quarters. How many coins of each type does he have?
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

three more quarters than dimes and twice as many nickels as quarters

Let x,(x+3), 2(x+3)represent the number of dimes, quarters and nickels respectively

Question states***Note: Cents makes sense

10x+ 25(x+3)+ 5*2(x+3) = 375 CENTS

Solving for x

 45x + 75 + 30 = 375

   45x = 270

      x = 6, the number of dimes. 9 Quarters and 18 Nickels



CHECKING our Answer***

 10*6 + 25*9 + 5*18 = 60 + 225 + 90 =  375 or $3.75