Question 406109: i need help solving this problem.
find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two. Answer by ewatrrr(24785) (Show Source):
Hi
Let x,(x+1),(x+2) represent the 3 consecutive numbers
Question states***
4x = (x+1)+(x+2)+7
Solving for x
2x = 10
x = 5 The 3 consecutive numbers are 5,6,7
CHECKING our Answer***
20 = 13+7