You can put this solution on YOUR website! graph the ellipse and its foci x^2/9 + y^2/4=1
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standard forms of ellipse:
(x-h)^2/a^2+(y-k)^2/b^2=1 (horizontal major axis),a>b
(y-k)^2/a^2+(x-h)^2/b^2=1 (vertical major axis),a>b
given ellipse has horizontal major axis
center:(0,0)
a^2=9
a=3
b^2=4
b=2
c=sqrt(a^2-b^2)=sqrt(9-4)=sqrt(5)=2.24
foci=(-2.24,0),(2.24,0)
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see graph of given ellipse below:
y=((36-4x^2)^.5)/3
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