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Question 40585: I am stumped on this question. Can someone please help me with it.
Find the equation, in standard form, including all integer coefficients, of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1).
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation, in standard form, including all integer coefficients, of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1).
3x-4y=9
y=(4y+9)/3
y=(4/3)y+3
slope = 4/3
The line perpendicular to the given line must have a slope = -3/4.
The form of the line equation must be y=mx+b where m=-3/4,x=-2,y=-1
Therefore -1=(3/4)(-2)+b
b-3/2 = -1
b=1/2
EQUATION of the line you want is
y=(-3/4)x+1/2
To put this in standard form, multiply thru by 4 to get:
4y=-3x+2
Then 3x+4y=2 (standard form of a line is ax+by=c)
Cheers,
Stan H.
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