You can put this solution on YOUR website! Find the value of z such that approximately 13.31% of the distribution lies between it and the mean.
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Draw a normal curve and put the mean in the middle.
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Shade an area of 13.31% to the left of the mean.
That has a left tale of 50-13.31 = 36.69%
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Find the z-value with a left tail of 36.69%:
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z = invNorm(0.3669) = -0.3401
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Similarly, if you shade the area on the
right side of the mean you will get a
z-value of +0.3401
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Cheers,
Stan H.
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