Question 405405: The perimeter of a rectangle is 46m. the length is 8m more than twice the width. find the dimensions.
Answer by IWork4Dessert(60)   (Show Source):
You can put this solution on YOUR website! You know that the perimeter of a rectangle is all of its sides added together.
Let's have the width be "w" and the length be "2w+8", as it's eight more than twice the width.
Now, there are two lengths(2w+8) and two widths(w) in a rectangle, so if you add them together that gives you the perimeter.
Just put your values into an equation.
(w)+(w)+(2w+8)+(2w+8)=46
6w+16=46
6w=30
Divide by both sides.
w=5
Your width is 5 and your length is 2w+8, so 10+8, 18.
Hope this helps!
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