Question 405377: 2/z-3+3/3z-9=0
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! 2/z-3 + 3/3z-9 = 0
2/z - 3 + 3/3(z - 3) = 0 {factored 3z - 9 into 3(z - 3)}
3(z - 3)[2/z - 3 + 3/3(z - 3) = 0] {multiplied entire equation by LCD, 3(z - 3)}
3(z - 3)[2/(z - 3)] + 3(z - 3)[3/3(z - 3)] = 3(z - 3)(0) {multiplied each term by 3(z - 3)}
6 + 3 = 0 {cancelled and multiplied}
9 = 0 {simplified}
= no solution
When the variable disappears and you get a statement that is never true,
then there is no solution.
When the variable disappears and you get a statement that is always true,
then there are infinite solutions.
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