SOLUTION: Find the x intercepts of y=x^2-4x+4

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Question 40537: Find the x intercepts of y=x^2-4x+4
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+x%5E2+-+4x+%2B+4
0+=+x%5E2+-+4x+%2B+4
0+=+x%5E2+-+2x+-+2x+%2B+4
0+=+%28x%5E2+-+2x%29+%2B+%28-2x+%2B+4%29
0+=+x%28x+-+2%29+-+2%28x+-+2%29
0+=+%28x+-+2%29%28x+-+2%29
The x-intercept is at 2.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-4x%2B4+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-4%29%5E2-4%2A1%2A4=0.

Discriminant d=0 is zero! That means that there is only one solution: x+=+%28-%28-4%29%29%2F2%5C1.
Expression can be factored: 1x%5E2%2B-4x%2B4+=+1%28x-2%29%2A%28x-2%29

Again, the answer is: 2, 2. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-4%2Ax%2B4+%29