SOLUTION: Simplify 2sqrt12 + 4sqrt27. I am coming up with an answer of 5sqrt3 - is this correct? I have the 2sqrt12 broken down to 2sqrt3 and 4sqrt27 broken down to3sqrt3. That is wh

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Simplify 2sqrt12 + 4sqrt27. I am coming up with an answer of 5sqrt3 - is this correct? I have the 2sqrt12 broken down to 2sqrt3 and 4sqrt27 broken down to3sqrt3. That is wh      Log On


   

Question 40534: Simplify
2sqrt12 + 4sqrt27.
I am coming up with an answer of 5sqrt3 - is this correct?
I have the 2sqrt12 broken down to 2sqrt3 and 4sqrt27 broken down to3sqrt3. That is where I got my answer from, by adding those.
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify
2sqrt12 + 4sqrt27
=2sqrt(4*3) + 4 sqrt (9*3)
=4sqrt3 + 12sqrt3
16sqrt3
Cheers,
Stan H.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
2sqrt12+4sqrt27 or 2sqrt(4*3)+4sqrt(9*3) removing the sqrt numbers from the radical we get 2*2sqrt3+4*3sqrt3 or
4sqrt3+12sqrt3 or (4+12)sqrt3 or 16sqrt3