SOLUTION: The selling price of x number of a certain stereo can be modeled by the function R(x)=150x. The total cost of making x stereo is C(x)=90x-0.02x^2. What is the percent markup for 60

Algebra ->  Rational-functions -> SOLUTION: The selling price of x number of a certain stereo can be modeled by the function R(x)=150x. The total cost of making x stereo is C(x)=90x-0.02x^2. What is the percent markup for 60      Log On


   

Question 40522: The selling price of x number of a certain stereo can be modeled by the function R(x)=150x. The total cost of making x stereo is C(x)=90x-0.02x^2. What is the percent markup for 60 stereos?
I don't know where to start? Please explain. Thanks
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The percent markup would be
[(selling price) - (cost to make) / (cost to make)] x 100
%28150x+-+%2890x+-+.02x%5E2%29%29+%2F+%2890x+-+.02x%5E2%29 =
%28150x+%2F+%2890x+-+.02x%5E2%29%29+-+1 =
%28150+%2F+%2890+-+.02x%29%29+-+1
find percent markup for x = 60
%28150+%2F+%2890+-+1.2%29%29+-+1 =
%28150%2F88.8%29+-+1
1.689+-+1 = .689
percent markup is 100 x .689, or about 69%