SOLUTION: a couple purchased two NHL hockey tickets and two NBA tickets for 153.92 A hockey ticket cost 4.32 more than a basketball ticket. What were the prices of the individual tickets?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: a couple purchased two NHL hockey tickets and two NBA tickets for 153.92 A hockey ticket cost 4.32 more than a basketball ticket. What were the prices of the individual tickets?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 405198: a couple purchased two NHL hockey tickets and two NBA tickets for 153.92 A hockey ticket cost 4.32 more than a basketball ticket. What were the prices of the individual tickets?
Answer by Jstrasner(112) About Me  (Show Source):
You can put this solution on YOUR website!
Hey,
So for this one you need to write two equations:
2NHL + 2NBA = 153.92
1NHL = 4.32 + 1NBA
You can substitute 4.32 + 1NBA for 1NHL in the first equation:
2(4.32 + 1NBA) + 2NBA= 153.92 => 8.64 + 2NBA + 2NBA = 153.92
Simplified: 8.64 + 4NBA = 153.92
Then you subtract 8.64 from both sides and get:
4NBA = 145.28
Then divide both sides by 4 and you get: 1NBA = 36.32
Since 1 NHL ticket is 4.32 more than 1 NBA ticket:
1NHL = 36.32 + 4.32 = 40.64
So:
1 NHL ticket costs 40.64
1 NBA ticket costs 36.32
I hope this helps!