SOLUTION: find the derivative ln x/ square root x^2 +1 y'=?

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Question 405158: find the derivative ln x/ square root x^2 +1
y'=?
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
y=%28ln%28x%29%29%2Fsqrt%28x%5E2%2B1%29
Use formulas: (u/v)'=(u'v-uv')/v^2
__________%28lnx%29'=1%2Fx
__________%28sqrt%28u%29%29'=%281%2F%282sqrt%28u%29%29%29%2Au'
__________%28x%5En%29'=n%2Ax%5E%28n-1%29, C'=0
y'=%28%28ln%28x%29%29%2Fsqrt%28x%5E2%2B1%29%29'=(%28ln%28x%29%29'sqrt%28x%5E2%2B1%29-ln%28x%29%2A%28sqrt%28x%5E2%2B1%29%29')/%28sqrt%28x%5E2%2B1%29%29%5E2=