SOLUTION: The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court. show the equation setup

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court. show the equation setup      Log On


   

Question 404939: The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court.
show the equation setup
Answer by IWork4Dessert(60) About Me  (Show Source):
You can put this solution on YOUR website!
Let length equal "w+34" and width equal "w".
You know that the total perimeter is 268 feet and that you need to add all sides together to get the perimeter. Thus:
(w+34)+(w+34)+w+w=268 feet
4w+68=268
4w=200
w=50
Now plug it back in.
w=50
w+34=84
And there's your answer.
width=50
length=84
You can also plug it back in to make sure it's right.
84+84+50+50=268
168+100=268
268=268 √