Question 404843: solve this system of equations using either addition or substitution. thanks your help!!!!!!!!!
2m = n - 3
3m = 2n - 9
please show me how to check also!i keep messing up on that part also.
Answer by algebra help tutor(6)   (Show Source):
You can put this solution on YOUR website! Let's solve this system by using the process of elimination by subtraction. We will eliminate the n variable by multiplying the top equation by 2 and then subtracting the two equations.
2(2m=n-3)
3m=2n-9
4m=2n-6
- 3m=2n-9
m=3 Remember, -6-(-9) is -6+9, so the answer is 3.
To solve for n, substitute m=3 into any of the original equations.
2m=n-3
2(3)=n-3
6 =n-3
+3 +3 Addition property of equality
9 =n
So the answer is (3,9)
To check your answer, plug the point into both of the equations and see if they make sense.
2m=n-3 2(3)=9-3
6=6 checks out:)
3m=2n-9 3(3)=2(9)-9
9=18-9
9=9 checks out also:)
|
|
|
