SOLUTION: how to solve 3x=7^(log7(6))

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Question 404799: how to solve 3x=7^(log7(6))
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Since 7^x and log%287%2C+x%29 are inverse functions, they cancel out and the right side of the equation is equal to 6. Thus, 3x = 6 --> x = 2.