Question 404679: write the equation in standard form. name the center, the length of the minor and major axis, and direction.
5x^2+9y^2=720
x^2+9y^2-4x+54y+49=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! write the equation in standard form. name the center, the length of the minor and major axis, and direction.
5x^2+9y^2=720
x^2+9y^2-4x+54y+49=0
..
5x^2+9y^2=720
divide by 720
x^2/144+y^2/80=1(standard form)
This is an ellipse with:
center (0,0),major axis horizontal because a>b
a^2=144
a=12
b^2=80
b=sqrt(80)
length of major axis,=2a=24
length of minor axis, 2b =2Sqrt(80)
..
x^2+9y^2-4x+54y+49=0
complete the squares
(x^2-4x+4)+9(y^2+6y+9)=-49+4+81
(x-2)^2+9(y+3)^2=36
(x-2)^2/36+(y+3)^2/4=1 (standard form)
This is an ellipse with:
center (2,-3), major axis horizontal
a^2=36
a=6
b^2=4
b=2
length of major axis,=2a=12
length of minor axis, 2b =4
|
|
|
