Multiply two of these three factors. (And since multiplication is Commutative and Associative we can pick any two factors to multiply to start!)
Multiply the answer from step 1 by the remaining factor.
Since we get to pick which pair of factors to multiply I am going to pick the easiest pair. The last two factors, (x+3) and (x-3), fit the pattern for . So multiplying them will be easy. Using the pattern, with "a" being x and "b" being 3 we get:
or
Now we multiply what is left. There is no pattern for this. Since it is one binmial times another we can use FOIL. But before that I like to rewrite the subtractions as additions. Subtractions are a common source of confusion and errors.
Now we'll use FOIL:
which simplifies as follows:
Usually terms are put in descending order of the exponents so this would become:
(