SOLUTION: In how many ways can we form three groups of people from 5 people, with each of the two groups consisting of 2 people, and the last group with only one person?
In how many way
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-> SOLUTION: In how many ways can we form three groups of people from 5 people, with each of the two groups consisting of 2 people, and the last group with only one person?
In how many way
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Question 404520: In how many ways can we form three groups of people from 5 people, with each of the two groups consisting of 2 people, and the last group with only one person?
In how many ways can we form 4 groups of people from 11 people, where one group consists of 4 people, another group has 3 people, and each of the two remaining groups consisting of 2 people?
The order of the grouping doesn't matter. Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website! 1)
no. of ways to arrange 5 people on 3 groups = 5C2 * 3C2 * 1C1 / 2! = 15
here two groups has 2 people each and order of the grouping doesn't matter.
2)
no. of ways to make a group of 4 people from 11= 11C4
no. of ways to make a group of 3 people from remaining 7 = 7C3
no. of ways to make a group of 2 people from remaining 4 = 4C2
no. of ways to make a group of 2 people from remaining 2 = 2C2
and here 2 groups of 2 people and order of group doesn't matter
no. of ways to arrange 11 people on 4 groups = 11C4 * 7C3 * 4C2 * 2C2 /2!
= 34650
try to understand the concept and solve it yourself....
