SOLUTION: A jar contains quarters and nickels. There are 15 more nickels than quarters. The total value is $2.55. Find how many of each coin type there are. (4 steps)
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: A jar contains quarters and nickels. There are 15 more nickels than quarters. The total value is $2.55. Find how many of each coin type there are. (4 steps)
Log On
Question 404472: A jar contains quarters and nickels. There are 15 more nickels than quarters. The total value is $2.55. Find how many of each coin type there are. (4 steps) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let n = no. of nickels
let q = no. of quarters
:
Write an equation for each statement:
:
" There are 15 more nickels than quarters."
n = (q+15)
:
"The total value is $2.55."
.05n + .25q = 2.55
Replace n with (q+15)
.05(q+15) + .25q = 2.55
.05q + .75 + .25q = 2.55
.05q + .25q = 2.55 - .75
.30q = 1.80
q =
q = 6 quarters
then
n = 6 + 15
n = 21 nickels
:
:
Check this
.05(21) + .25(6) =
1.05 + 1.50 = 2.55