SOLUTION: Solve to the nearest hundredth: e^(x+2)=6 When I did the work, I got (x+2)ln e=6 x+2=6 x=4 **I think this is wrong t

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve to the nearest hundredth: e^(x+2)=6 When I did the work, I got (x+2)ln e=6 x+2=6 x=4 **I think this is wrong t      Log On


   

Question 404461: Solve to the nearest hundredth: e^(x+2)=6
When I did the work, I got (x+2)ln e=6
x+2=6
x=4
**I think this is wrong though. Please help! Thanks! :)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
+e%5E%28x%2B2%29=6
%28x%2B2%29%2Aln+e+=+ln+6.
==> x%2B2+=+ln+6
That's where the glitch is.