SOLUTION: solve for x to the nearest thousandth: ln(5x+20)=2

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Question 404441: solve for x to the nearest thousandth: ln(5x+20)=2
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
ln(5x+20)=2
Solving equations where the variable is in the argument of a logarithm, like this equation, usually starts with transforming the equation into one of the following forms:
log(expression) = other-expression
or
log(expression) = log(other-expression)

Your equation is already in the first form. So we can proceed to the next step, which is to rewrite the equation in exponential form. In general log%28a%2C+%28p%29%29+=+q is equivalent to p+=+a%5Eq. Using this pattern on your equation (and using the fact that the base of ln is "e") we get:
5x%2B20+=+e%5E2
We can now solve for x. Subtracting 20 from each side we get:
5x+=+e%5E2+-+20
Dividing by 5 we get:
x+=+%28e%5E2+-+20%29%2F5
This is an exact expression of the solution to your equation. You are asked to find a decimal (approximation). So get out your calculator. (If your calculator does not have a button for the number "e", use 2.7182818284590451 (or some rounded off version of it).)