SOLUTION: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height h in feet after t seconds is given by the equation h=-16t(squared)+108t.
At what
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At what
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Question 404393: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height h in feet after t seconds is given by the equation h=-16t(squared)+108t.
At what time will the ball hit the ground? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! set h to zero and solve for t:
0=-16t^2+108t
0=-4t(4t-27)
t= {0,27/4}
.
solution is 27/4 seconds
or
6.75 seconds
