SOLUTION: How do I solve the following: Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and log6 ≈0.778. Use the properties of logarithms to evaluate the expression: Log24

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: How do I solve the following: Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and log6 ≈0.778. Use the properties of logarithms to evaluate the expression: Log24       Log On


   

Question 404276: How do I solve the following:
Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and log6 ≈0.778.
Use the properties of logarithms to evaluate the expression:
Log24
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Step 1
Rewrite 24 as a product of 4 and 6.
= log+%284+%2A+6%29
Step 2
Use the Product+Property.
= log+4+%2B+log+6
Step 3
Substitute 0.602 for log+4 and 0.778 for log+6.

= 0.602+%2B+0.778
=+1.38

so, log+%2824%29=+1.38