SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a stat

Algebra ->  Average -> SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a stat      Log On


   

Question 404226: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 8:10 AM. If train B passes the same station at 8:40 am, what time will train B catch up to train A?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Train A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour.
Train A passes a station at 8:10 AM. If train B passes the same station at
8:40 am, what time will train B catch up to train A?
:
from the given information, we know that train B is 30 min (1/2 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: 1%2F2 * 88 = 44 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 44 mi
88t = 80t + 44
88t - 80t = 44
8t = 44
t = 44%2F8
t = 5.5 hr or 5 hr 30 min
:
8:10 AM + 5:30 = 1:30 pm, B catches A
:
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Feedback to Student comment. "I figure it to be 1:40, are you sure about your answer?"
:
Check solution of 5.5 hrs,
:
Train B should travel 44 mi more that Train A in the same time
:
Train B: 88 * 5.5 = 484 mi
Train A: 80 * 5.5 = 440 mi
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Difference in dist: 44 mi