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Question 404142: For what positive numbers will the cube of a number exceed 7 times its square?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! For what positive numbers will the cube
of a number exceed 7 times its square?
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Solve x^3>7x^2
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x^3-7x^2 > 0
x^2(x-7) > 0
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x = 0 is not a solution.
So, x^2 must be positive.
Since the product is positive x-7 must be positive.
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Solve x-7 > 0
Ans: x > 7
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Cheers,
Stan H.
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