SOLUTION: Write the equation of a line that is perpendicular to the given line and that passes through the given point. 4x+12y=-24;(-3,2)

Algebra ->  Graphs -> SOLUTION: Write the equation of a line that is perpendicular to the given line and that passes through the given point. 4x+12y=-24;(-3,2)      Log On


   

Question 403991: Write the equation of a line that is perpendicular to the given line and that passes through the given point.
4x+12y=-24;(-3,2)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
4x+%2B+12y+=+-24
12y+=+-4x+-+24
y+=+-%281%2F3%29%2Ax+-+2
The slope is -%281%2F3%29
Any line perpendicular to this line
has slope =-%281%2Fm%29, where m
is the given slope.
-%281%2F%28-%281%2F3%29%29%29+=+3
The line I'm looking for has slope = 3, and
goes through (-3,2)
use the point-slope formula
%28y+-+2%29+%2F+%28x+-+%28-3%29%29+=+3
y+-+2+=+3%2A%28x+%2B+3%29
y+=+3x+%2B+9+%2B+2
y+=+3x+%2B+11 answer
check:
Does line go through (-3,2)?
y+=+3x+%2B+11
2+=+3%2A%28-3%29+%2B+11
2+=+-9+%2B+11
2+=+2
OK