SOLUTION: The area of a rectangle is 35. If the length is 2 more than the width, find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The area of a rectangle is 35. If the length is 2 more than the width, find the dimensions of the rectangle.      Log On


   

Question 403881: The area of a rectangle is 35. If the length is 2 more than the width, find the dimensions of the rectangle.
Answer by texttutoring(324) About Me  (Show Source):
You can put this solution on YOUR website!
L=w+2

Area = Lw
35 = (w+2)w
35 = w^2 +2w
0 = w^2 + 2w -35
Factor (or use the quadratic formula):
0=(w+7)(w-5)
w=-7, w=5
The width can't be a negative number, so we can't choose w=-7. The width must be 5.

We know that the length is 2 more than the width, so the length must be 7.

Dimensions:
L=7
w=5

Area = 7x5=35