Question 403833: (2+3i)/(-4i)+(2+4i)/(1+i)
Answer by CharlesG2(834)   (Show Source):
You can put this solution on YOUR website! (2+3i)/(-4i)+(2+4i)/(1+i)
(2 + 3i) / (-4i) + (2 + 4i) / (1 + i)
(2 + 3i)(4i) / (-4i)(4i) + (2 + 4i)(1 - i) / (1 + i)(1 - i)
used conjugates since division, conjugate of a+bi is a-bi
i^2 = -1
used FOIL, First Outer Inner Last, to multiply binonials
(-12 + 8i) / 16 + (2 - 2i + 4i + 4) / (1 + 1)
(-3/4) + (1/2)i + (6 + 2i) / 2
(-3/4) + (1/2)i + 3 + i
(9/4) + (3/2)i
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