SOLUTION: Using the graph, determine the value of y when x=4. The graph shows a forward slanting line the crosses -3 on the y-axis and 1.5 on x axis.. how do i figure this out?

Algebra ->  Graphs -> SOLUTION: Using the graph, determine the value of y when x=4. The graph shows a forward slanting line the crosses -3 on the y-axis and 1.5 on x axis.. how do i figure this out?      Log On


   



Question 403757: Using the graph, determine the value of y when x=4.
The graph shows a forward slanting line the crosses -3 on the y-axis and 1.5 on x axis..
how do i figure this out?

Found 2 solutions by nerdybill, MathLover1:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Find 4 on the x-axis.
Then, go straight up until you hit the slant line.
then, go horizontally (to the left) until you hit the y-axis.
Where you connect with the y-axis is your answer (should be 5)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

given:
Using the graph, determine the value of y when x=4.
line the crosses -3 on the y-axis...means you have one point at (0,-3)
and 1.5 on x axis....means you have second point at (1.5, 0)
now, we can find EQUATION of straight line given 2 points

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, -3) and (x2, y2) = (1.5, 0).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%280--3%29%2F%281.5-0%29+=+2.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 2%2A0+%2Bb+=+-3. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-3-2%2A0+=+-3.

y=(2)x + (-3)

Your graph:





from the graph you can see, if you draw a line parallel to y-axis from the point 4 it will cross your line at y=5

that is the value of y when x=4; your third point is (4,5)


let's check if all three your points are collinear (lie on same line)

Solved by pluggable solver: To determine if 3 points lie in a line
The 3 points lie on a same plane. For all points to lie on a line they should satisfy the equation of a line. Hence any two points taken on a line should calculate to the same slope of a line.

In order to prove the 3 points to lie on a line, as there exists a unique line containing three points and every line has a unique slope.
Hence it will be sufficient to prove that the slope calculated taking 2 points at a time should be equal.


Slope of line taking points (X1,Y1) and (X2,Y2) is

slope+=+%28Y2-Y1%29%2F%28X2-X1%29


slope+=+%28%280--3%29%2F%281.5-0%29%29+=+2 ........................(1)



Slope of line taking points (X3,Y3) and (X1,Y1) is

slope+=+%28Y3-Y1%29%2F%28X3-X1%29


slope+=+%28%285--3%29%2F%284-0%29%29+=+2 ........................(2)



From conditions (1) and (2)


The slopes are equal hence the 3 points can lie on same line.


If the slope calculated from points (X2,Y2) and (X3,Y3) comes out to be same then it is confirmed that the 3 points lie on a same line.



slope+=+%28Y3-Y2%29%2F%28X3-X2%29


slope+=+%28%285-0%29%2F%284-1.5%29%29+=+2 ........................(3)


From (1),(2) and (3)

Hence, It is proved that the 3 points lie on same line.


To read more on equations of a line refer to articles on wikipedia