SOLUTION:
a container has 2 liters of 21% solution sodium hydroxide.
what is the amount and concentration you must add to this in order to
end up with 7 liters of 51% solution?
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a container has 2 liters of 21% solution sodium hydroxide.
what is the amount and concentration you must add to this in order to
end up with 7 liters of 51% solution?
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Question 403725:
a container has 2 liters of 21% solution sodium hydroxide.
what is the amount and concentration you must add to this in order to
end up with 7 liters of 51% solution? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
a container has 2 liters of 21% solution sodium hydroxide.
what is the amount and concentration you must add to this in order to
end up with 7 liters of 51% solution?
.
Well, you know you must add 5 liters so the only question is the concentration.
Let x = concentration
then
.21(2) + 5x = .51(7)
.42 + 5x = 3.57
5x = 3.15
x = 0.63
.
Solution: 5 liters of 63% solution sodium hydoxide
