SOLUTION: a sparrow flies to see a friend at a speed of 4km/h. his friend is out,so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how many f

Algebra ->  Expressions-with-variables -> SOLUTION: a sparrow flies to see a friend at a speed of 4km/h. his friend is out,so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how many f      Log On


   



Question 403723: a sparrow flies to see a friend at a speed of 4km/h. his friend is out,so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how many far away does his friend Live?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

let distance be x km
while going to meet 4km/h
time taken = x/4
...
return speed = 5km/h
time = x/5
...
x/5 +x/4 = 54/60
(4x+5x)/20=54/60
9x=54*20/60
9x=18
/9
x= 2km====> distance friend lives