Question 403546: To win the lottery you ,must pick six numbers from 49 balls numbered 1-49. The order in which you pick the balls doesn’t matter. How many different combinations can you pick?
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! To win the lottery you ,must pick six numbers from 49 balls numbered 1-49. The order in which you pick the balls doesn’t matter. How many different combinations can you pick?
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49C6 = 49!/[(49-6)!*6!] = (49*48*47*46*45*44)/(1*2*3*4*5*6) = 13,983,816
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Cheers,
Stan H.
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Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! The 1st is 1 of 49.
Then 1 of 48, 47, 46, etc, since the numbers don't repeat (ie, you can't have 2 35's).
--> 49*48*47*46*45*44 = a big number
Since order doesn't matter, there are 6 chances to pick any particular, so the big number is divided by 6*5*4*3*2*1 = 720
The # of combinations = 13983816
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This is 49!/(43!*6!), or 49C6
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