SOLUTION: How do I use the Intercept Form to find the equation of the line with: 1) X-intercept= -3 and Y-intercept= 2 2) X-intercept= 5 and Y-intercept= 6 Thank you!

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Question 403350: How do I use the Intercept Form to find the equation of the line with:
1) X-intercept= -3 and Y-intercept= 2
2) X-intercept= 5 and Y-intercept= 6
Thank you!
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

1) X-intercept= -3 and Y-intercept= 2

X-intercept: -3 means that the point (-3,0) is on the line

Y-intercept: 2 means that the point (0,2) is on the line


So let's find the equation of the line through the points (-3,0) and (0,2)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, 0) and (x2, y2) = (0, 2).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0.666666666666667%2A-3+%2Bb+=+2. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0-0.666666666666667%2A-3+=+2.

y=(0.666666666666667)x + (2)

Your graph:






2) X-intercept= 5 and Y-intercept= 6

let's find the equation of the line through the points (5,0) and (0,6)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 0) and (x2, y2) = (0, 6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-0%29%2F%280-5%29+=+-1.2.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1.2%2A5+%2Bb+=+6. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0--1.2%2A5+=+6.

y=(-1.2)x + (6)

Your graph: